-16t^2+28t+60=60

Solution for -16t^2+28t+60=60 equation:

-16t^2+28t+60=60

We move all terms to the left:

-16t^2+28t+60-(60)=0

We add all the numbers together, and all the variables

-16t^2+28t=0

a = -16; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-16)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-16}=\frac{-56}{-32}
=1+3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-16}=\frac{0}{-32}
=0
$